On 07.07.2022 19:02, Roger L Costello costello@xxxxxxxxx wrote:
I have an XSD simpleType with enumeration values:
<xsd:simpleType name="RunwayLightingType">
<xsd:restriction base="xsd:string">
<xsd:enumeration value="1"/>
<xsd:enumeration value="2"/>
<xsd:enumeration value="3"/>
<xsd:enumeration value="4"/>
<xsd:enumeration value="5"/>
<xsd:enumeration value="6"/>
<xsd:enumeration value="7"/>
<xsd:enumeration value="8"/>
<xsd:enumeration value="9"/>
<xsd:enumeration value="10"/>
<xsd:enumeration value="11"/>
<xsd:enumeration value="12"/>
</xsd:restriction>
</xsd:simpleType>
I want to turn the values into a regex such that the longest value (not the
biggest value, the string longest value) is listed first:
12|11|10|9|8|7|6|5|4|3|2|1
Seems like a simple problem, right? Should have a simple solution, right?
Well, I devised a solution, but it sure ain't simple.
string-join(for $i in reverse(sort(xs:restriction/xs:enumeration, (),
function($enum) {string-length($enum/@value )})) return $i/@value, '|')
Is there is a simpler XPath expression to solve this problem?
Is 12 longer than 11 or 10?
As for simpler, the ! and => operators are supposed to allow for more
compact and easier to read expressions.
|
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