Hi Roger,

> Well, I devised a solution, but it sure ain't simple.
>
>   string-join(for $i in reverse(sort(xs:restriction/xs:enumeration, (),
function($enum) {string-length($enum/@value )})) return $i/@value, '|')
>
>   Is there is a simpler XPath expression to solve this problem?

I think this can be written in a good and readable way as below:

string-join(
                  sort(/*/xs:restriction/xs:enumeration/@value,
                         (),
                          function($s) {- string-length($s)}) ,
                   '|'
                 )

Thanks,
Dimitre

On Thu, Jul 7, 2022 at 10:02 AM Roger L Costello costello@xxxxxxxxx <
xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> wrote:

> Hi Folks,
>
> I have an XSD simpleType with enumeration values:
>
> <xsd:simpleType name="RunwayLightingType">
>   <xsd:restriction base="xsd:string">
>    <xsd:enumeration value="1"/>
>    <xsd:enumeration value="2"/>
>    <xsd:enumeration value="3"/>
>    <xsd:enumeration value="4"/>
>    <xsd:enumeration value="5"/>
>    <xsd:enumeration value="6"/>
>    <xsd:enumeration value="7"/>
>    <xsd:enumeration value="8"/>
>    <xsd:enumeration value="9"/>
>    <xsd:enumeration value="10"/>
>    <xsd:enumeration value="11"/>
>    <xsd:enumeration value="12"/>
>   </xsd:restriction>
>  </xsd:simpleType>
>
> I want to turn the values into a regex such that the longest value (not
> the biggest value, the string longest value) is listed first:
>
> 12|11|10|9|8|7|6|5|4|3|2|1
>
> Seems like a simple problem, right? Should have a simple solution, right?
>
> Well, I devised a solution, but it sure ain't simple.
>
> string-join(for $i in reverse(sort(xs:restriction/xs:enumeration, (),
> function($enum) {string-length($enum/@value )})) return $i/@value, '|')
>
> Is there is a simpler XPath expression to solve this problem?
>
> /Roger