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Fabien Tillier wrote:
What could be the XPath expression to get the maximum number of nodes of level=50 in data those keycode starts like the level=40 line ? Here the answer would be 3 as the maximum number of level = 50 nodes for a given level = 40 is 3 As you originally asked for an XPath expression here is a more compact form of the previous suggestion: <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="2.0"> <xsl:param name="l1" select="'50'"/> <xsl:param name="l2" select="'40'"/> <xsl:key name="k1" match="row" use="level"/> <xsl:template match="/"> <xsl:value-of select="max( for $group in key('k1', $l2) return count(key('k1', $l1)[starts-with(keycode, $group/keycode)]) )"/> </xsl:template> </xsl:stylesheet> -- Martin Honnen http://msmvps.com/blogs/martin_honnen/
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