Hi Martin
Clever....
Wish I could find it myself :)

Best regards,
Fabien



-----Message d'origine-----
De : Martin Honnen [mailto:Martin.Honnen@xxxxxx]
Envoyi : mardi 23 novembre 2010 16:09
@ : xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Objet : Re:  selecting nodes based on sibling values

Fabien Tillier wrote:

> <data>
> 	<row>
> 		<level>40</level>
> 		<keycode>1254.45.12</keycode>
> 	</row>
> 	<row>
> 		<level>50</level>
> 		<keycode>1254.45.12.7</keycode>
> 	</row>
> 	<row>
> 		<level>50</level>
> 		<keycode>1254.45.12.8</keycode>
> 	</row>
> 	<row>
> 		<level>50</level>
> 		<keycode>1254.45.12.9</keycode>
> 	</row>
>
> 	<row>
> 		<level>40</level>
> 		<keycode>99.25.6</keycode>
> 	</row>
> 	<row>
> 		<level>50</level>
> 		<keycode>99.25.6.45</keycode>
> 	</row>
> 	<row>
> 		<level>50</level>
> 		<keycode>99.25.6.46</keycode>
> 	</row>
> </data>
>
> What could be the XPath expression to get the maximum number of nodes of
> level=50 in data those keycode starts like the level=40 line ?
> Here the answer would be 3 as the maximum number of level = 50 nodes for
> a given level = 40 is 3

The following outputs "3" for your sample:

<xsl:stylesheet
   xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
   version="2.0">

   <xsl:param name="l1" select="'50'"/>
   <xsl:param name="l2" select="'40'"/>

   <xsl:key name="k1" match="row" use="level"/>

   <xsl:template match="/">
     <xsl:variable name="groups" as="element(group)*">
       <xsl:for-each select="key('k1', $l2)">
         <group>
           <xsl:copy-of select="key('k1', $l1)[starts-with(keycode,
current()/keycode)]"/>
         </group>
       </xsl:for-each>
     </xsl:variable>
     <xsl:value-of select="max($groups/count(row))"/>
   </xsl:template>

</xsl:stylesheet>

--

	Martin Honnen
	http://msmvps.com/blogs/martin_honnen/