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I am very inexperienced, using XSLT 2.0 with Saxon B9.0.0.6 in Oxygen on
Windows Vista. I have Michael Kay's book, but do not know enough to find the
answer to my question on my own.
I want to do a simple sort without losing either elements or attributes. The xls style sheet I have written works, but there must be a more succinct method. One element <Cat> has four attributes (two optional), the other <Person> has one optional attribute. When the templates for <Cat> and <Person> are not present in my style sheet, I lose the attributes but not the elements themselves. Is the answer somewhere in apply-templates? Without the two templates, when I tried <xsl:apply-templates select="@* | node()"/>, I got the value of the attributes as a list within the start tags but without their names. Did I miss something? Thanks for any help, Mark <?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="2.0"> <xsl:output method ="xml" /> <xsl:strip-space elements="*"/> <xsl:template match="*">
<xsl:copy>
<xsl:apply-templates>
<xsl:sort select="Year" />
<xsl:sort select="IssueNumber"/>
<xsl:sort select="Page" />
</xsl:apply-templates>
</xsl:copy>
</xsl:template> <xsl:template match="Cat">
<xsl:element name="Cat">
<xsl:attribute name="pofis">
<xsl:value-of select="@pofis" />
</xsl:attribute>
<xsl:attribute name="pofis-number">
<xsl:value-of select="@pofis-number" />
</xsl:attribute>
<xsl:if test="@pofis-range">
<xsl:attribute name="pofis-range">
<xsl:value-of select="@pofis-range" />
</xsl:attribute>
</xsl:if>
<xsl:if test="@pofis-prefix">
<xsl:attribute name="pofis-prefix">
<xsl:value-of select="@pofis-prefix" />
</xsl:attribute>
</xsl:if>
<xsl:value-of select="node()" />
</xsl:element>
</xsl:template><xsl:template match="Person"> <xsl:element name="Person"> <xsl:if test="@is-author"> <xsl:attribute name="is-author"> <xsl:value-of select="@is-author" /> </xsl:attribute> </xsl:if> <xsl:value-of select="node()"/> </xsl:element>
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