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Mark Wilson wrote:
I want to do a simple sort without losing either elements or attributes. The xls style sheet I have written works, but there must be a more If you want to copy everything but also want to make some changes then you usually start with a template for the identity transformation <xsl:template match="@* | node()"> <xsl:copy> <xsl:apply-templates select="@* | node()"/> </xsl:copy> </xsl:template> then you add templates for the changes. Thus if you want process the child elements of an element sorted on Year, IssueNumber, Page, as the template below suggests then you need to make sure you process attributes as well: <xsl:template match="*">
<xsl:copy>
<xsl:apply-templates select="@*"/>
<xsl:apply-templates>
<xsl:sort select="Year" />
<xsl:sort select="IssueNumber"/>
<xsl:sort select="Page" />
</xsl:apply-templates>
</xsl:copy>
</xsl:template>On the other hand you probably don't want to sort for all elements that way so I would rather expect something like <xsl:template match="foo">
<xsl:copy>
<xsl:apply-templates select="@*"/>
<xsl:apply-templates>
<xsl:sort select="Year" />
<xsl:sort select="IssueNumber"/>
<xsl:sort select="Page" />
</xsl:apply-templates>
</xsl:copy>
</xsl:template>to suffice, where foo is the name of the element whose children you want to process sorted. -- Martin Honnen http://JavaScript.FAQTs.com/
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