Maybe because text files can be UNIX escaped (\n), dos (\r\n) or mac
(can't remember).

Anyway regex are awsome !

2 cents,
-Mathieu

On 10/10/07, Michael Kay <mike@xxxxxxxxxxxx> wrote:
> I've no idea of the history that caused "." to have this meaning, but your
> observation is correct. To make "." match a newline, use flags="s" on the
> xsl:analyze-string instruction.
>
> Michael Kay
> http://www.saxonica.com/
>
> > -----Original Message-----
> > From: Mathieu Malaterre [mailto:mathieu.malaterre@xxxxxxxxx]
> > Sent: 10 October 2007 11:29
> > To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> > Subject:  xsl:analyze-string and line break
> >
> > Hello,
> >
> >   I am trying to do a regex on an expression with line
> > breaks, for some reason '.' does not include line break. I
> > also tried [.\n]* to say anything including line break, with no luck.
> >
> > xml file is:
> >
> > <?xml version="1.0"?>
> > <description>Sex of the named patient. Enumerated Values:
> >  M = male
> >  F = female
> >  O = other</description>
> >
> >
> > and xsl file is:
> > <?xml version="1.0"?>
> > <xsl:transform
> > xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="2.0">
> >   <xsl:output method="xml" indent="yes"/>
> >   <xsl:template name="parse-enum">
> >     <xsl:param name="text"/>
> >     <xsl:analyze-string select="$text" regex="\n">
> >       <xsl:matching-substring>
> > <!--br/-->
> >       </xsl:matching-substring>
> >       <xsl:non-matching-substring>
> >         <enum>
> >           <xsl:value-of select="."/>
> >         </enum>
> >       </xsl:non-matching-substring>
> >     </xsl:analyze-string>
> >   </xsl:template>
> >   <xsl:template match="/description">
> >     <xsl:analyze-string select="." regex=".*Enumerated
> > Values:([.\n]*)">
> >       <xsl:matching-substring>
> >         <xsl:value-of select="regex-group(1)"/>
> >       </xsl:matching-substring>
> >     </xsl:analyze-string>
> >   </xsl:template>
> > </xsl:transform>
> >
> > Thanks,
> >
> >
> >
> > --
> > Mathieu
>
>


-- 
Mathieu