Hello,

  I am trying to do a regex on an expression with line breaks, for
some reason '.' does not include line break. I also tried [.\n]* to
say anything including line break, with no luck.

xml file is:

<?xml version="1.0"?>
<description>Sex of the named patient. Enumerated Values:
 M = male
 F = female
 O = other</description>


and xsl file is:
<?xml version="1.0"?>
<xsl:transform xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="2.0">
  <xsl:output method="xml" indent="yes"/>
  <xsl:template name="parse-enum">
    <xsl:param name="text"/>
    <xsl:analyze-string select="$text" regex="\n">
      <xsl:matching-substring>
<!--br/-->
      </xsl:matching-substring>
      <xsl:non-matching-substring>
        <enum>
          <xsl:value-of select="."/>
        </enum>
      </xsl:non-matching-substring>
    </xsl:analyze-string>
  </xsl:template>
  <xsl:template match="/description">
    <xsl:analyze-string select="." regex=".*Enumerated Values:([.\n]*)">
      <xsl:matching-substring>
        <xsl:value-of select="regex-group(1)"/>
      </xsl:matching-substring>
    </xsl:analyze-string>
  </xsl:template>
</xsl:transform>

Thanks,



-- 
Mathieu