Subject: Re: translate to XML using XSL into an HTML table
From: Steve <subsume@xxxxxxxxx>
Date: Fri, 3 Aug 2007 16:03:23 -0400
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There's a solution to fill in //LAST and //PHONE with their
corresponding //FIRSTs but I'm hard pressed to produce it now, given
that your XML <listing /> doesn't encapsulate 1 member but several. If
you have control over the XML I'd wrap <member /> around each FIRST,
LAST, PHONE pair.
Perhaps someone else will chime in.
-S
On 8/3/07, oryann9 <oryann9@xxxxxxxxx> wrote:
> > <xsl:for-each select="//LISTING"> should match both
> > listings (...I believe).
> > Can you post some idea of your output HTML?
> > I'm guessing <tr><td>first</td><td>last</td></tr>
>
> My Phone Book
> ------------------
> FIRST|LAST|PHONE
> ------------------
> Derek|
> Steve|
> Corey|
> Tiko |
> Kurt |
> Jane |
> ------------------
>
> is from
>
> <?xml version="1.0"?>
> <xsl:stylesheet version="1.0"
> xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
> <xsl:output method="html"/>
> <xsl:template match="/">
> <html>
> <head>
> <title> My Phone Book</title>
> </head>
> <h2> My Phone Book </h2>
> <body bgcolor="YELLOW">
> <table border="3">
> <tr bgcolor="lightblue">
> <th>FirstName</th>
> <th>LastName</th>
> <th>Phone</th>
> </tr>
> <xsl:for-each select="//FIRST">
> <tr>
> <td><xsl:value-of select="."/></td>
> </tr>
> </xsl:for-each>
> </table>
> </body>
> </html>
> </xsl:template>
> </xsl:stylesheet>
>
>
>
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