Subject: Re: translate to XML using XSL into an HTML table
From: oryann9 <oryann9@xxxxxxxxx>
Date: Fri, 3 Aug 2007 12:51:27 -0700 (PDT)
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> <xsl:for-each select="//LISTING"> should match both
> listings (...I believe).
> Can you post some idea of your output HTML?
> I'm guessing <tr><td>first</td><td>last</td></tr>
My Phone Book
------------------
FIRST|LAST|PHONE
------------------
Derek|
Steve|
Corey|
Tiko |
Kurt |
Jane |
------------------
is from
<?xml version="1.0"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="html"/>
<xsl:template match="/">
<html>
<head>
<title> My Phone Book</title>
</head>
<h2> My Phone Book </h2>
<body bgcolor="YELLOW">
<table border="3">
<tr bgcolor="lightblue">
<th>FirstName</th>
<th>LastName</th>
<th>Phone</th>
</tr>
<xsl:for-each select="//FIRST">
<tr>
<td><xsl:value-of select="."/></td>
</tr>
</xsl:for-each>
</table>
</body>
</html>
</xsl:template>
</xsl:stylesheet>
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