Subject: Re: node is in a nodelist?
From: "Dimitre Novatchev" <dnovatchev@xxxxxxxxx>
Date: Tue, 19 Jun 2007 06:23:49 -0700
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On 6/19/07, Kai Hackemesser <kaha@xxxxxx> wrote:
I understand. But with key() as nodelist this is less performant than
David's solution, isn't it?
There are node-sets composed of nodes belonging to different documents
(or even belonging to no document at all).
<xsl:key .../> only indexes the nodes of a single document (at a
time) and the key() function returns a node-set of nodes, all
belonging to a single document.
Therefore, the expressions provided by Dr. Kay are more universal.
--
Cheers,
Dimitre Novatchev
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Truly great madness cannot be achieved without significant intelligence.
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To invent, you need a good imagination and a pile of junk
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You've achieved success in your field when you don't know whether what
you're doing is work or play
Ciao!
kai
Michael Kay schrieb:
>> How do I know in a easy way if a node is in a nodelist (for
>> example returned by key())?
>>
>
> In XSLT 2.0: exists($node intersect $nodelist)
>
> In 1.0: count($node | $nodelist) = count($nodelist)
>
> Michael Kay
> http://www.saxonica.com/
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