Re: [xsl] node is in a nodelist?

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Subject: Re: node is in a nodelist?
From: Kai Hackemesser <kaha@xxxxxx>
Date: Tue, 19 Jun 2007 13:27:36 +0200

I understand. But with key() as nodelist this is less performant than David's solution, isn't it?

Ciao!
kai

Michael Kay schrieb:

How do I know in a easy way if a node is in a nodelist (for example returned by key())?
In XSLT 2.0: exists($node intersect $nodelist)

In 1.0: count($node | $nodelist) = count($nodelist)
Michael Kay
http://www.saxonica.com/

Current Thread
node is in a nodelist? Kai Hackemesser - 19 Jun 2007 09:08:16 -0000 David Carlisle - 19 Jun 2007 09:14:34 -0000 Kai Hackemesser - 19 Jun 2007 09:21:37 -0000 Michael Kay - 19 Jun 2007 10:25:37 -0000 Kai Hackemesser - 19 Jun 2007 11:28:07 -0000 <= Michael Kay - 19 Jun 2007 13:11:49 -0000 Dimitre Novatchev - 19 Jun 2007 13:24:08 -0000

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