Abel Braaksma wrote:

  Hi

> Abel Braaksma wrote:

> > Michael Kay wrote:

> >> $fib[1] = 0 and $fib[2] = 1 and
> >>   every $i in 2 to count($fib) satisfies
> >>     $fib[$i] = $fib[$i - 1] + $fib[$i - 2]

> Here's another version, which eases the expression a bit
> by removing the special cases:

> every $i in 1 to count($fib) satisfies
>        $fib[$i] = (0, $fib)[$i] + (0, 1, $fib)[$i]

  Personally, I like the first version.  The second one is
shorter, but the first one as is almost a literal
translation from the mathematical definition.  But it is a
matter of taste, I guess.

  Regards,

--drkm



















	

	
		
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