I'm using version two and I got the correct output (each network address
once).  Maybe something wrong with XMLSpy's parser?  I'm using Saxon 8.1.

--Jim Neff 

> -----Original Message-----
> From: Craig W [mailto:codecraig@xxxxxxxxx] 
> Sent: Wednesday, March 02, 2005 9:12 AM
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject: Re:  Sorting network addresses
> 
> well, i changed the xslt version from 2.0 to 1.0 and i get 
> the correct output....i wonder why?  FYI, XMLSpy be default 
> uses its own XSLT engine (for either 1.0 or 2.0), or you can 
> specify that it uses Microsoft's XML parser, or you can have 
> it use some other XSL transformation program that you specify.
> 
> Anyway, thanks for the help....it would still be nice to know 
> why version 2.0 is acting differently.
> 
> -Craig
> 
> 
> On Wed, 2 Mar 2005 14:05:20 GMT, David Carlisle 
> <davidc@xxxxxxxxx> wrote:
> > 
> > 
> > > ....now do u get what i get?
> > no I get:
> > 
> > $ saxon ip2.xml ip2.xsl
> > <?xml version="1.0" encoding="UTF-8"?> <networks> <network> 
> > <address>1.1.1.1</address> </network> <network> 
> > <address>2.3.1.2</address> </network> <network> 
> > <address>170.5.2.4</address> </network> </networks>
> > 
> > But I just noticed that you are specifying XSLT2 (although 
> you don't 
> > have any xslt2 specific features) so I'll try with saxon8:
> > 
> > I get same:
> > 
> > $ java -jar ../saxon8/saxon8.jar  ip2.xml ip2.xsl <?xml 
> version="1.0" 
> > encoding="UTF-8"?> <networks> <network> <address>1.1.1.1</address> 
> > </network> <network> <address>2.3.1.2</address> </network> 
> <network> 
> > <address>170.5.2.4</address> </network> </networks>
> > 
> > > To repeat how I did it,
> > > open the XML document, go to the "XSL/XQuery"
> > 
> > sorry that would mean downloading xmlspy first which is too much:-)
> > 
> > What processor does it use for XSLT2 ?
> > 
> > David
> > 
> > 
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