Subject: Re: Understanding Identity Transformations
From: David Carlisle <davidc@xxxxxxxxx>
Date: Sun, 13 Feb 2005 18:30:23 GMT
|
Tempore 14:47:08, die 02/13/2005 AD, hinc in
xsl-list@xxxxxxxxxxxxxxxxxxxxxx scripsit David Carlisle <davidc@xxxxxxxxx>:
> If A is a node set with two or more nodes that are not string-equal
> then A != x is always true for any value of x.
That's interesting... So you can use not(A!=B) to check if all nodes in
two node-sets A and B are stingwise identical; Now isn't this a good use
of '!=' ?
not(A!=B) is true just if A!=B is false which is only the case if every
node in A is equal to every node in B. If that's what you want to test
for then the expression is put to good use, but it's rather rare to have
a node set where all the nodes are string equal (unless it's something
like @abc where you know there is at most one node in the set).
David
________________________________________________________________________
This e-mail has been scanned for all viruses by Star. The
service is powered by MessageLabs. For more information on a proactive
anti-virus service working around the clock, around the globe, visit:
http://www.star.net.uk
________________________________________________________________________
|