Subject: Re: Understanding Identity Transformations
From: "Joris Gillis" <roac@xxxxxxxxxx>
Date: Sun, 13 Feb 2005 18:16:35 +0100
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Tempore 14:47:08, die 02/13/2005 AD, hinc in
xsl-list@xxxxxxxxxxxxxxxxxxxxxx scripsit David Carlisle <davidc@xxxxxxxxx>:
If A is a node set with two or more nodes that are not string-equal
then A != x is always true for any value of x.
That's interesting... So you can use not(A!=B) to check if all nodes in
two node-sets A and B are stingwise identical; Now isn't this a good use
of '!=' ?
regards,
--
Joris Gillis (http://www.ticalc.org/cgi-bin/acct-view.cgi?userid=38041)
Laudeo W3C et dona ferens
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