If the format is completely predictable,

concat(substring(.,1,20), substring(.,24))

- I may have counted wrong.

If less predictable, use the replace() function in 2.0 or some combination
of substring-after() and substring-before() in 1.0.

Alternatively, in 2.0, cast to an xs:dateTime, extract the components using
e.g. seconds-from-dateTime(), modify the seconds value, and reconstruct.

Michael Kay
http://www.saxonica.com/ 

> -----Original Message-----
> From: Bhaskar, Rajan [mailto:RBhaskar@xxxxxxx] 
> Sent: 02 February 2005 22:29
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject: RE:  String formatting
> 
> sorry in this form
> yyyy-MM-DDThh:mm:ss.SSS-HH:mm          but want to translate to 
> yyyy-MM-DDThh:mm:ss-HH:mm       removing the SSS
> 
> 
> 
> -----Original Message-----
> From: Bhaskar, Rajan [mailto:RBhaskar@xxxxxxx]
> Sent: Wednesday, February 02, 2005 5:26 PM
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject:  String formatting
> 
> 
> 
> Hi,
>  I have a string in the form=20
> yyyy-MM-DDThh:mm:ss.SSS-HH:mm  but want to translate to=20
> yyyy-MM-DDThh:mm:ss-HH:mm  removing the SSS.
> 
> How can i do that.
> 
> thanks,
> Rajan