Subject: RE: HOW XSLT WILL BE, WHEN XML2XML TRANSFORMATION
From: "Michael Kay" <mike@xxxxxxxxxxxx>
Date: Sat, 4 Dec 2004 16:11:26 -0000
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This is very straightforward.
<xsl:template match="para">
<xsl:apply-templates/>
</xsl:template>
<xsl:template match="equation">
<eqn><xsl:apply-templates/></eqn>
</xsl:template>
<xsl:template match="para/text()">
<p><xsl:apply-templates/></p>
</xsl:template>
Michael Kay
http://www.saxonica.com/
>
> I am processing XML to XML transformation by using xslt, in
> the meantime
> I would like to clarify with you regarding the below one:
>
> Input XML:
> <para>
> Text before equation
> <equation>Equation text</equation>
> Text before/after equation
> <equation>Equation text</equation>
> Text after equation
> </para>
>
>
> Output XML:
> <p>Text before equation</p>
> <eqn>Equation text</eqn>
> <p>Text before/after equation</p>
> <eqn>Equation text</eqn>
> <p>Text after equation</p>
>
> Please advise, how can I able to get above Output XML by
> using xslt, and
> how the XSLT will be?
>
> Best regards
> Arul Kumar
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