Subject: Re: HOW XSLT WILL BE, WHEN XML2XML TRANSFORMATION
From: Marian Olteanu <mou_softwin@xxxxxxxxx>
Date: Sat, 4 Dec 2004 02:34:37 -0800 (PST)
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--- Arul Kumar <arulxml@xxxxxxxxxxxx> wrote:
> Hallow everybody,
>
> I am processing XML to XML transformation by using xslt, in the meantime
> I would like to clarify with you regarding the below one:
>
> Input XML:
> <para>
> Text before equation
> <equation>Equation text</equation>
> Text before/after equation
> <equation>Equation text</equation>
> Text after equation
> </para>
>
>
> Output XML:
> <p>Text before equation</p>
> <eqn>Equation text</eqn>
> <p>Text before/after equation</p>
> <eqn>Equation text</eqn>
> <p>Text after equation</p>
>
> Please advise, how can I able to get above Output XML by using xslt, and
> how the XSLT will be?
>
> Best regards
> Arul Kumar
I would say:
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>
<?xml version='1.0'?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="para/text()">
<p>
<xsl:value-of select="."/>
</p>
</xsl:template>
<xsl:template match="para/equation">
<eqn>
<xsl:apply-templates/>
</eqn>
</xsl:template>
</xsl:stylesheet>
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-----------------------------------
Marian
http://www.utdallas.edu/~mgo031000/
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