Hi,

> The a and b elements are always there but there might be some 
> (d) elements 
> before the c element: a/b/d/c, perhaps a/b/d/e/f/c.
> 
> Kan I in the solution below, just substitute a/b/c with a/b//c?

In the key match you can use

  <xsl:key name="uniq" match="c" use="." />

if c is not used as a non-countable item. If a/b//c selects all the c elements you want, then it'll work.

Cheers,

Jarno - Clan of Xymox: I Want You Now

 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list