I believe this is not possible.  XSLT doesn't allow you
to use a variable for an XPath expression.  See number 2 at
the following list:

http://www.dpawson.co.uk/xsl/sect2/nono.html

> -----Original Message-----
> From: bix xslt [mailto:bix_xslt@xxxxxxxxxxx]
> Sent: Tuesday, December 17, 2002 1:32 PM
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject: Re:  combining two variables to generate XPATH
> 
> 
> Please note I made a slight correction.  the $node that 
> appears within the 
> foreach statment just under the branch variable assignment 
> should be $branch 
> instead.  This does not solve my problem - this is the 
> original problem.  
> Thanks.
> 
> 
> >From: "bix xslt" <bix_xslt@xxxxxxxxxxx>
> >        <xsl:variable name="branch" 
> >select="concat($node,'/',$type,'/item')" />
> >        <xsl:value-of select="$branch" />
> ><!--        <xsl:for-each select="$node">
> 
> becomes
> 
> >        <xsl:variable name="branch" 
> >select="concat($node,'/',$type,'/item')" />
> >        <xsl:value-of select="$branch" />
> ><!--        <xsl:for-each select="$branch">
> 
> 
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