Re: [xsl] combining two variables to generate XPATH

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Subject: Re: combining two variables to generate XPATH
From: "bix xslt" <bix_xslt@xxxxxxxxxxx>
Date: Tue, 17 Dec 2002 19:31:51 +0000

Please note I made a slight correction. the $node that appears within the foreach statment just under the branch variable assignment should be $branch instead. This does not solve my problem - this is the original problem. Thanks.

From: "bix xslt" <bix_xslt@xxxxxxxxxxx> <xsl:variable name="branch" select="concat($node,'/',$type,'/item')" /> <xsl:value-of select="$branch" /> <!-- <xsl:for-each select="$node">

becomes

<xsl:variable name="branch" select="concat($node,'/',$type,'/item')" /> <xsl:value-of select="$branch" /> <!-- <xsl:for-each select="$branch">

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Current Thread
combining two variables to generate XPATH bix xslt - Tue, 17 Dec 2002 14:12:53 -0500 (EST) <Possible follow-ups> bix xslt - Tue, 17 Dec 2002 14:32:39 -0500 (EST) <= Jeff Kenton - Tue, 17 Dec 2002 15:03:51 -0500 (EST) Mark Wilgus - Tue, 17 Dec 2002 14:43:19 -0500 (EST) bix xslt - Tue, 17 Dec 2002 15:04:52 -0500 (EST) Wendell Piez - Tue, 17 Dec 2002 15:29:03 -0500 (EST)

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