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Joerg Heinicke wrote:
From Joerg's example: It is my understanding that if you have: <a> <f id="1"/> <f id="2"/> <f id="2"/> </a> and you happen to be on the 3rd f node you would get: preceding-sibling::field/@id=1 and current()/@id=2 but if you use: preceding-sibling::field[1]/@id=2 Is this wrong? -Rob XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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