I was afraid that might be the answer.
Thanks for taking the time to consider my problem.

Is there any other way to force the key() function to refer to the nodes in $old_file? The name of the old file is being passed into the stylesheet as a parameter, so I don't believe it can be directly referenced in <xsl:key>.

<xsl:key> works per XML tree, you don't specify a special one (or a document) in the key-declaration. With your <xsl:for-each select="$oldfile"> you only change the context document for the key to work on.

So there is no work around if there is really a bug in XSLTC. Either you use the inefficient method or must wait until the bug is fixed.

Joerg


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