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Is there any other way to force the key() function to refer to the nodes in $old_file? The name of the old file is being passed into the stylesheet as a parameter, so I don't believe it can be directly referenced in <xsl:key>. <xsl:key> works per XML tree, you don't specify a special one (or a document) in the key-declaration. With your <xsl:for-each select="$oldfile"> you only change the context document for the key to work on. So there is no work around if there is really a bug in XSLTC. Either you use the inefficient method or must wait until the bug is fixed. Joerg XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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