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Subject: Re: for-each order
From: Trevor Nash <tcn@xxxxxxxxxxxxx>
Date: Fri, 14 Dec 2001 17:24:18 +0000
>Is there a way to do <xsl:for-each ..... and looping backwards.
>

Use xsl:sort, as in:

><xsl:variable name="position">
>   <xsl:for-each select="$path">
       <xsl:sort select="position()" data-type="number"
order="descending" />
>      <xsl:value-of select="@value"/>,
>   </xsl:for-each>
></xsl:variable>

(Ref: Mike Kay's XSLT programmers reference, page 297)

Anticipating the obvious question if you want 1,2,3 instead of 1,2,3,
  <xsl:if test="position()!=last()">,</xsl:if>

Regards,
Trevor Nash
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Current Thread
  • for-each order
    • Charly - Fri, 14 Dec 2001 11:34:20 -0500 (EST)
      • Jeni Tennison - Fri, 14 Dec 2001 12:12:18 -0500 (EST)
      • Trevor Nash - Fri, 14 Dec 2001 12:27:25 -0500 (EST) <=
      • Michael Kay - Fri, 14 Dec 2001 12:35:16 -0500 (EST)
      • <Possible follow-ups>
      • McNally, David - Fri, 14 Dec 2001 12:30:57 -0500 (EST)
        • Trevor Nash - Fri, 14 Dec 2001 14:00:16 -0500 (EST)
          • TP - Fri, 14 Dec 2001 14:42:35 -0500 (EST)
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