Subject: Re: for-each order
From: Trevor Nash <tcn@xxxxxxxxxxxxx>
Date: Fri, 14 Dec 2001 17:24:18 +0000
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>Is there a way to do <xsl:for-each ..... and looping backwards.
>
Use xsl:sort, as in:
><xsl:variable name="position">
> <xsl:for-each select="$path">
<xsl:sort select="position()" data-type="number"
order="descending" />
> <xsl:value-of select="@value"/>,
> </xsl:for-each>
></xsl:variable>
(Ref: Mike Kay's XSLT programmers reference, page 297)
Anticipating the obvious question if you want 1,2,3 instead of 1,2,3,
<xsl:if test="position()!=last()">,</xsl:if>
Regards,
Trevor Nash
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| Current Thread |
- for-each order
- Charly - Fri, 14 Dec 2001 11:34:20 -0500 (EST)
- Jeni Tennison - Fri, 14 Dec 2001 12:12:18 -0500 (EST)
- Trevor Nash - Fri, 14 Dec 2001 12:27:25 -0500 (EST) <=
- Michael Kay - Fri, 14 Dec 2001 12:35:16 -0500 (EST)
- <Possible follow-ups>
- McNally, David - Fri, 14 Dec 2001 12:30:57 -0500 (EST)
- Trevor Nash - Fri, 14 Dec 2001 14:00:16 -0500 (EST)
- TP - Fri, 14 Dec 2001 14:42:35 -0500 (EST)
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