Subject: Re: for-each order
From: Trevor Nash <tcn@xxxxxxxxxxxxx>
Date: Fri, 14 Dec 2001 18:37:32 +0000
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>Caveat: I'm a relative newbie, still weaning myself off disable output
>escaping....
>
Keep at it! ;-))
>There are a variety of ways of reversing things - just search on the archive
>for reverse, or see
>http://sources.redhat.com/ml/xsl-list/2001-08/msg00243.html
>
>but in this particular case I'm thinking that this (untested) might work:
>
> <xsl:variable name="position">
> <xsl:for-each select="$path">
> <xsl:sort order="descending" select="position()"/>
Very close. The data-type="number" is important, otherwise item 10
sorts next to item 1.
> <xsl:value-of select="@value"/>,
> </xsl:for-each>
> </xsl:variable>
>
>David.
Regards,
Trevor Nash
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| Current Thread |
- Re: for-each order, (continued)
- Jeni Tennison - Fri, 14 Dec 2001 12:12:18 -0500 (EST)
- Trevor Nash - Fri, 14 Dec 2001 12:27:25 -0500 (EST)
- Michael Kay - Fri, 14 Dec 2001 12:35:16 -0500 (EST)
- McNally, David - Fri, 14 Dec 2001 12:30:57 -0500 (EST)
- Trevor Nash - Fri, 14 Dec 2001 14:00:16 -0500 (EST) <=
- TP - Fri, 14 Dec 2001 14:42:35 -0500 (EST)
- Joerg Heinicke - Fri, 14 Dec 2001 15:53:26 -0500 (EST)
- TP - Mon, 17 Dec 2001 12:30:56 -0500 (EST)
- Michael Kay - Mon, 17 Dec 2001 14:54:02 -0500 (EST)
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