This can be done with:

<xsl:template match="/ | * | @* | text()">
        <whatever/>
                <xsl:copy>
                        <xsl:apply-templates select="*|@*|text()"/>
                </xsl:copy>
        <whatever/>
</xsl:template>

-----Message d'origine-----
De:     xsl-list@xxxxxxxxxxxxxxxx 
Date:   jeudi 9 mars 2000 18:00
À:      xsl-list@xxxxxxxxxxxxxxxx
Objet:  XML -> XSL -> same XML

How do I transform an XML with an XSL that spits out the same XML document
that was inputted, except with a particular heading or footer.  Is there any way
I can do this without re-specifying every XML tag in the XSL?


 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list

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