Subject: Copying unparsed entity using XSL
From: Bovone Stefano <Stefano.Bovone@xxxxxxxx>
Date: Thu, 11 Nov 1999 16:08:53 +0100
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I have a xml document like this:
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE Job SYSTEM "doc.dtd" [
<!ENTITY pcl0001 SYSTEM "pcl0001.pcl" NDATA BINARY>
]>
<Job>
<Print/>
</Job>
I would like to obtain the identity trasformation using something like:
<xsl:template match="@* | node()">
<xsl:copy>
<xsl:apply-templates select="@* | node()"/>
</xsl:copy>
</xsl:template>
but I want that the Entity:
<!ENTITY pcl0001 SYSTEM "pcl0001.pcl" NDATA BINARY>
is in the output file.
Is this possible using XSLT (and XT or LotusXSL or ..) ?
Thanks in advance.
Bye.
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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