Hello,

I'm not sure of the second step, but the first one is likely:

<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE Job SYSTEM "doc.dtd" [
<!ENTITY pcl0001 SYSTEM "pcl0001.pcl" NDATA BINARY>
<!ATTLIST Print file ENTITY #REQUIRED>
]>

<Job>
   <Print file="pcl0001"/>
</Job>

Richard.


-----Original Message-----
From: owner-xsl-list@xxxxxxxxxxxxxxxx
[mailto:owner-xsl-list@xxxxxxxxxxxxxxxx]On Behalf Of Bovone Stefano
Sent: Thursday, November 11, 1999 10:09 AM
To: 'XSL-List@xxxxxxxxxxxxxxxx'
Subject: Copying unparsed entity using XSL 


I have a xml document like this:

<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE Job SYSTEM "doc.dtd" [
<!ENTITY pcl0001 SYSTEM "pcl0001.pcl" NDATA BINARY>
]>

<Job>
   <Print/>
</Job>

I would like to obtain the identity trasformation using something like:

<xsl:template match="@* | node()">
 <xsl:copy>
  <xsl:apply-templates select="@* | node()"/>
 </xsl:copy>
</xsl:template>

but I want that the Entity:

<!ENTITY pcl0001 SYSTEM "pcl0001.pcl" NDATA BINARY>

is in the output file.

Is this possible using XSLT (and XT or LotusXSL or ..) ?

Thanks in advance.

Bye.


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 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list