• From: cmarchand@o...
• To: Michael Kay <mike@s...>
• Date: Thu, 09 Mar 2017 12:41:22 +0100

Ok, thanks a lot to all of you.
Best regards,
Christophe

Le 2017-03-09 11:46, Michael Kay a écrit :

It would be nice if XSD allowed a type to be specified on a wildcard,
but sadly it doesn't. I can't think of any good reason why not.

Michael Kay
Saxonica

On 9 Mar 2017, at 09:07, cmarchand@o... wrote:

Hello,

I have a complexType definition, Foe.

In another complexType, I want to allow any child element, but require that each child element is valid against Foe definition.

Something like :

<xs:complexType name="Foe">
<xs:attribute name="start" type="xs:positiveInteger" use="required"/>
<xs:attribute name="end" type="xs:positiveInteger" use="required"/>
<xs:assert test="@end ge @start">
</xs:complexType>

<xs:complexType name="parent">
<xs:sequence>
<xs:any type="Foe"/>
</xs:sequence>
</xs:complexType>

How can I do this ?

Thanks,
Christophe

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• References:
  • XML Schema - How to define any element of type Foe
    • From: cmarchand@o...
  • Re: XML Schema - How to define any element of type Foe
    • From: Michael Kay <mike@s...>