• From: Michael Kay <mike@s...>
• To: cmarchand@o...
• Date: Thu, 9 Mar 2017 10:46:47 +0000

It would be nice if XSD allowed a type to be specified on a wildcard, but sadly it doesn't. I can't think of any good reason why not.

Michael Kay
Saxonica

> On 9 Mar 2017, at 09:07, cmarchand@o... wrote:
> 
> Hello,
> 
> I have a complexType definition, Foe.
> 
> In another complexType, I want to allow any child element, but require that each child element is valid against Foe definition.
> 
> Something like :
> 
> <xs:complexType name="Foe">
>  <xs:attribute name="start" type="xs:positiveInteger" use="required"/>
>  <xs:attribute name="end" type="xs:positiveInteger" use="required"/>
>  <xs:assert test="@end ge @start">
> </xs:complexType>
> 
> <xs:complexType name="parent">
>  <xs:sequence>
>    <xs:any type="Foe"/>
>  </xs:sequence>
> </xs:complexType>
> 
> How can I do this ?
> 
> Thanks,
> Christophe
> 
> _______________________________________________________________________
> 
> XML-DEV is a publicly archived, unmoderated list hosted by OASIS
> to support XML implementation and development. To minimize
> spam in the archives, you must subscribe before posting.
> 
> [Un]Subscribe/change address: http://www.oasis-open.org/mlmanage/
> Or unsubscribe: xml-dev-unsubscribe@l...
> subscribe: xml-dev-subscribe@l...
> List archive: http://lists.xml.org/archives/xml-dev/
> List Guidelines: http://www.oasis-open.org/maillists/guidelines.php

• Follow-Ups:
  • Re: XML Schema - How to define any element of type Foe
    • From: cmarchand@o...

• References:
  • XML Schema - How to define any element of type Foe
    • From: cmarchand@o...