Hi Mark,

On Wed, 31 Aug, 2022, 06:57 Mark Giffin m1879@xxxxxxxxxxxxx, <
xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> wrote:

> XSLT 2.0, Saxon processor.
>
>
>
> What's a good way to check if a variable has a value? I want to print
> something if a variable has a value, and not print it if it is not given a
> value. This must be extremely simple but I don't see it.
>

I think, we can simply compare XSLT 2.0+ variable's value with an empty
sequence.

i.e somthing like below,

<xsl:if test="not(deep-equals($var, ()))">
    <xsl:copy-of select="$var"/>
</xsl:if>

(this will output the contents of variable to XSLT result tree, which the
XSLT serializer could serialize to an XML fragment instance for example)

or,

<xsl:if test="not(deep-equals($var, ()))">
    <xsl: value-of select="diagnostic message"/>
</xsl:if>


--
Regards,
Mukul Gandhi



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