The below XSLT seems to work, but despite the xsl:output method="xml"
declaration, the files come out as .html (even though the contents are
fine).
I should have said, the files areB output with an HTML extension, even
though the XML structure remains intact.
Regards,
Chuck
What am I missing?
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
B <xsl:output method="xml" omit-xml-declaration="yes" indent="no"/>
<xsl:template match="dealt">
B <xsl:copy>
B <xsl:apply-templates select="@*"/>
B <xsl:apply-templates select="entry">
B B <xsl:sort select="@ID" order="ascending"/>
B </xsl:apply-templates>
B </xsl:copy>
</xsl:template>
<xsl:template match="@* | node()">
B <xsl:copy>
B <xsl:apply-templates select="@* | node()"/>
B </xsl:copy>
</xsl:template>
Regards,
Chuck
---------------------------
A. Charles Muller, Professor
Buddhist Culture Research Center
Musashino University
1-1-20 Shinmachi, Nishitokyo-shi
Tokyo 202-8585, Japan
Office Phone: 042-468-3145
(University of Tokyo, Professor Emeritus)
Web Site: Resources for East Asian Language and Thought
http://www.acmuller.net
Twitter: @ACharlesMuller
--
---------------------------
A. Charles Muller, Professor
Buddhist Culture Research Center
Musashino University
1-1-20 Shinmachi, Nishitokyo-shi
Tokyo 202-8585, Japan
Office Phone: 042-468-3145
(University of Tokyo, Professor Emeritus)
Web Site: Resources for East Asian Language and Thought
http://www.acmuller.net
Twitter: @ACharlesMuller
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