Re: [xsl] XPath expression to get the string following the o

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Subject: Re: XPath expression to get the string following the open quote of an attribute?
From: "Martin Honnen martin.honnen@xxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>
Date: Thu, 14 Jan 2021 16:17:58 -0000

On 14.01.2021 17:14, Roger L Costello costello@xxxxxxxxx wrote:

Here are sample input strings:
="abc"
= "abc"
=       "abc"
That is, an equals, zero or more whitespaces, quote, value, quote

I want everything after the first quote.

My neural network thinks that sounds like

substring-after($s, '"')

but perhaps I miss something that makes the requirements more complicated.

Current Thread
XPath expression to get the string following the open quote of an attribute? Roger L Costello costello@xxxxxxxxx - 14 Jan 2021 16:14:00 -0000 Martin Honnen martin.honnen@xxxxxx - 14 Jan 2021 16:17:58 -0000 <= Geert Bormans geert@xxxxxxxxxxxxxxxxxxx - 14 Jan 2021 16:33:20 -0000

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