Hi Martin,
That's an oversight on my part. Any elements outside of step elements have
to be processed individually. Can I change the for-each-group to just group
adjacent <step> elements? Thank you very much.
Rick
-----Original Message-----
From: Martin Honnen martin.honnen@xxxxxx
<xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>
Sent: Saturday, October 26, 2019 1:39 PM
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: Re: Feedback on grouping solution
On 26.10.2019 19:03, Rick Quatro rick@xxxxxxxxxxxxxx wrote:
> I need to process the <step> child elements so that the <figure>
> elements are always on the "right" (even-numbered position) in the
> output. Immediate children of the <procedure> do not factor into the
> odd/even sequence.
>
> The first child of each group of adjacent <step> elements starts a new
> odd/even series. To ensure that the each <figure> is in an
> even-numbered position, I want to insert a <spacer> element where it is
required.
>
> Here is my stylesheet. My basic question is: is there a better or more
> efficient way to do this? I really want to master grouping because it
> comes up in a lot of my tasks. Thank you for any input or criticism.
>
> <?xml version="1.0" encoding="UTF-8"?>
>
> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
>
> xmlns:xs="http://www.w3.org/2001/XMLSchema"
> exclude-result-prefixes="xs" version="2.0">
>
> <xsl:output indent="yes"/>
>
> <xsl:template match="/procedure">
>
> <procedure>
>
> <!-- Group the children of the procedure, keeping
> adjacent steps together. -->
>
> <xsl:for-each-group select="child::*"
> group-adjacent="local-name(.)">
>
> <xsl:choose>
>
> <xsl:when
> test="current-group()[1][not(self::step)]">
>
> <!-- Single element. -->
>
> <xsl:apply-templates
> select="current-group()[1]"/>
I don't understand this part, what is supposed to happen with two (or
more) adjacent <note/><note/> or other non step elements? Do you want to
drop any but the first of them?
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