Hello everybody and thank you very much for your good answers. They help
me to better understand XSL. I was also able to help myself with two
for-each loops: <?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:fn="http://www.w3.org/2005/xpath-functions" version="2.0"
exclude-result-prefixes="#all"> <xsl:output method="xml" encoding="UTF-8"
indent="yes"/> <xsl:template match="all">
<xsl:variable name="abbr" select="abbreviations/abbr"/>
<all>
<xsl:for-each select="//doc">
<xsl:variable name="actdoc" select="."/>
<xsl:variable name="no" select="@no"/>
<xsl:for-each select="$abbr">
<xsl:if test="fn:contains($actdoc, .)">
<doc no="{$no}">
<xsl:value-of select="."/>
</doc>
</xsl:if>
</xsl:for-each>
</xsl:for-each>
</all>
</xsl:template>
</xsl:stylesheet> Many greetings
Janine Gesendet: Freitag, 27. September 2019 um 12:46 Uhr
Von: "Mukul Gandhi gandhi.mukul@xxxxxxxxx"
<xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>
An: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Betreff: Re:  XSL | index-of()Hi Janine, Here's the stylesheet that
works, <?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
 xmlns:xs="http://www.w3.org/2001/XMLSchema"
 xmlns:fn="http://stylesheet_fns"
 exclude-result-prefixes="xs fn"
 version="2.0">

<xsl:output method="xml" indent="yes"/>

<xsl:template match="all">
 <all>
<xsl:for-each select="documents/doc[fn:isIncludeDoc(.)]">
 <doc no="{@no}"><xsl:value-of
select="substring-before(substring-after(., '('), ')')"/></doc>
</xsl:for-each>
 </all>
</xsl:template>

<xsl:function name="fn:isIncludeDoc" as="xs:boolean">
 <xsl:param name="doc" as="element(doc)"/>

 <xsl:sequence select="some $abbr in $doc/../../abbreviations/abbr
satisfies contains($doc, concat('(', $abbr, ')'))"/>
</xsl:function>

</xsl:stylesheet> On Fri, Sep 27, 2019 at 2:37 PM Janine Lantzsch
loderndesfeuer@xxxxxx <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> wrote:

  Hello community, I am new in this list and hope very much that
  someone can help me or give me an input with which I can continue to
  work.
  I would like to use XSL to check whether a abbreviation from a list
  appears in a certain string of recurring elements. The abbreviation
  is always written in brackets. The source file looks like this (very
  simplified): <?xml version="1.0" encoding="UTF-8"?>
  <all>
   <abbreviations>
   <abbr>ABG</abbr>
   <abbr>AGI</abbr>
   <abbr>BBL</abbr>
   <abbr>ECK</abbr>
   </abbreviations>
   <documents>
   <doc no="1">The abbreviation (ABG) appears in this doc.</doc>
   <doc no="2">This doc has no shortcut.</doc>
   <doc no="3">An abbreviation (BBL).</doc>
   <doc no="4">And here (ECK).</doc>
   <doc no="5">And here again (ECK).</doc>
   </documents>
  </all>
  Only unfortunately I still have a bug somewhere with the index-of.
  Maybe the more experienced of you will see right away what's wrong
  with my code. I've been brooding since last night and can't find a
  solution :( <?xml version="1.0" encoding="UTF-8"?>
  <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
  xmlns:fn="http://www.w3.org/2005/xpath-functions" version="2.0">
   <xsl:output method="xml" encoding="UTF-8"/>
   <xsl:template match="all">
   <xsl:variable name="abbr" select="abbreviations/abbr"/>
   <all>
   <xsl:for-each select="//doc">
   <xsl:variable name="actdoc" select="."/>
   <xsl:if test="fn:contains($actdoc, fn:index-of($abbr, $actdoc))">
   <doc>
   <xsl:attribute name="no"><xsl:value-of
  select="@no"/></xsl:attribute>
   <xsl:value-of select="$actdoc"/>
   </doc>
   </xsl:if>
   </xsl:for-each>
   </all>
   </xsl:template>
  </xsl:stylesheet>
  The output should look something like this: <all>
   <doc no="1">ABG</doc>
   <doc no="3">BBL</doc>
   <doc no="4">ECK</doc>
   <doc no="5">ECK</doc>
  </all>
  Thank you so much for your help! Many greetingsJanine S.

-- Regards,
Mukul GandhiXSL-List info and archiveEasyUnsubscribe (by email) XSL-List
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