On Fri, Mar 8, 2019 at 2:10 PM Michael Kay mike@xxxxxxxxxxxx <
xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> wrote:
> Because if $a is an empty sequence (which is the situation on the first
> call), then $a[last()] is an empty sequence, and ($x + ()) returns an empty
> sequence, not $x.
>
Thanks, for the explanation.
I came up with following as well, which works (though may be inefficient)
<xsl:variable name="inpValues" select="(1,2,3,4)" as="xs:integer*"/>
fold-left($inpValues, (), function($a, $b) {$a, sum(for $idx in 1 to
count($a) return $inpValues[$idx]) + $b})
--
Regards,
Mukul Gandhi
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