> On 7 Mar 2017, at 09:44, Dr. Patrik Stellmann patrik.stellmann@xxxxxxxxx
<xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> wrote:
>
> Hi Raimund,
>
> You could just replace the "l_name" by "concat(l_name, ' ', f_name)" within
the xsl:key, key() and xsl:sort.


A better solution is to use a multi-part sort key:

<xsl:for-each ...
   <xsl:sort select="l_name"/>
   <xsl:sort select="f_name"/>

The results will only be different if either

(a) your default collation ignores spaces, or

(b) the names you are sorting on include spaces

Michael Kay
Saxonica
>
>
> ------------------------------------------------------------------
> Systemarchitektur & IT-Projekte
> Tel: +49 40 33449-1142
> Fax: +49 40 33449-1400
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>
> -----UrsprC<ngliche Nachricht-----
> Von: Raimund Kammering raimund.kammering@xxxxxxx
[mailto:xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx]
> Gesendet: Dienstag, 7. MC$rz 2017 10:32
> An: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Betreff:  sort on one key - duplicates
>
> Hi Folks,
>
> I have an XSL which pulls out all last names and creates a sorted list of
these. Works fine, but now I noticed that for duplicated last names only the
first person is created in the output! So I need to also take the first name
into account! But Ibm lacking the idea to accomplish this! The XML, XSL
looks like this:
>
> <list>
>   <subject name=bA">
>      <person>
>         <l_name>Doe</l_name>
>         <f_name>John</f_name>
>         <expert/>
>         <mail>john.doe@xxxxxxxxxxxxx</mail>
>      </person>
>      <person>
>         <l_name>Doe</l_name>
>         <f_name>Johanna</f_name>
>         <expert/>
>         <mail>johanna.doe@xxxxxxxxxxxxx</mail>
>      </person>
>   </subject>
>
>   <subject name=bBb>
>     <person>
>         <l_name>Mueller</l_name>
>         <f_name>Michael</f_name>
>         <expert/>
>         <mail>michael.mueller@xxxxxxxxxxxxx</mail>
>      </person>
>      <person>
>         <l_name>Mueller</l_name>
>         <f_name>Joe</f_name>
>         <expert/>
>         <mail>joe.mueller@xxxxxxxxxxxxx</mail>
>      </person>
>   </subject>
> </list>
>
> with the following XSL
>
> <?xml version="1.0"?>
> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="2.0">
>
>  <xsl:output indent="yes" method="xml"/>
>
>  <!-- Needed to avoid duplicates in "All" subject see:             -->
>  <!-- http://www.jenitennison.com/xslt/grouping/muenchian.htm -->
>  <xsl:key name="l_names" match="subject/person" use="l_name"/>
>
>  <xsl:template match="/list">
>    <xsl:choose>
>      <xsl:when test="count(./*[@name='All']) = 0">
>        <xsl:element name="{name()}">
>          <xsl:element name="subject">
>            <xsl:attribute name="name">All</xsl:attribute>
>            <xsl:for-each select="subject/person[count(. | key('l_names',
l_name)[1]) = 1]">
>              <xsl:sort select="l_name"/>
>              <xsl:element name="person">
>                <xsl:copy-of select="l_name"/>
>                <xsl:copy-of select="f_name"/>
>                <xsl:element name="expert"/>
>                <xsl:copy-of select="mail"/>
>              </xsl:element>
>            </xsl:for-each>
>          </xsl:element>
>
>          <xsl:for-each select="subject">
>              <xsl:element name="{name()}">
>                <xsl:attribute name="name">
>                  <xsl:value-of select="@*"/>
>                </xsl:attribute>
>                <xsl:for-each select="person">
>                  <xsl:sort select="l_name"/>
>                  <xsl:copy-of select="."/>
>                </xsl:for-each>
>              </xsl:element>
>          </xsl:for-each>
>
>        </xsl:element>
>      </xsl:when>
>
>      <xsl:otherwise>
>        <xsl:element name="{name()}">
>        <xsl:for-each select="subject">
>            <xsl:element name="{name()}">
>              <xsl:attribute name="name">
>                <xsl:value-of select="@*"/>
>              </xsl:attribute>
>              <xsl:for-each select="person">
>                <xsl:sort select="l_name"/>
>                <xsl:copy-of select="."/>
>              </xsl:for-each>
>            </xsl:element>
>        </xsl:for-each>
>      </xsl:element>
>      </xsl:otherwise>
>
>    </xsl:choose>
>  </xsl:template>
>
> </xsl:stylesheet>
>
>
> <list>
>   <subject name=bAll">
>      <person>
>         <l_name>Doe</l_name>
>         <f_name>John</f_name>
>         <expert/>
>         <mail>john.doe@xxxxxxxxxxxxx</mail>
>      </person>
>     <person>
>         <l_name>Mueller</l_name>
>         <f_name>Michael</f_name>
>         <expert/>
>         <mail>michael.mueller@xxxxxxxxxxxxx</mail>
>      </person>
>   </subject>
>
>   <subject name=bA">
>      <person>
>         <l_name>Doe</l_name>
>         <f_name>John</f_name>
>         <expert/>
>         <mail>john.doe@xxxxxxxxxxxxx</mail>
>      </person>
>      <person>
>         <l_name>Doe</l_name>
>         <f_name>Johanna</f_name>
>         <expert/>
>         <mail>johanna.doe@xxxxxxxxxxxxx</mail>
>      </person>
>   </subject>
>
>   <subject name=bBb>
>     <person>
>         <l_name>Mueller</l_name>
>         <f_name>Michael</f_name>
>         <expert/>
>         <mail>michael.mueller@xxxxxxxxxxxxx</mail>
>      </person>
>      <person>
>         <l_name>Mueller</l_name>
>         <f_name>Joe</f_name>
>         <expert/>
>         <mail>joe.mueller@xxxxxxxxxxxxx</mail>
>      </person>
>   </subject>
> </list>
>
> which produces the requested output except for that in the bAllb list is
only filled the first one of a person which name is appearing multiple times!
>
> So I need to in addition to the key on l_name need to also take the f_name
into account!
>
> Raimund
>
>
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