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On 09.01.2017 15:25, Steve Wisniewski stevewiz76@xxxxxxxxx wrote:
My question is, how can I sort the groups so that they are sorted in value order like this: you can store the result in a variable and then sort it <xsl:variable name="rows" as="element(tr)*"> <xsl:for-each-group select="location[(xs:integer(class) eq 1) or (xs:integer(class) eq 2)]" group-by="city"> <tr> <td>1-2</td> <td><xsl:value-of select="format-number(sum(current-group()/value),'$###,###')"/></td> </tr> </xsl:for-each-group> <xsl:for-each-group select="location[(xs:integer(class) gt 2) and (xs:integer(class) lt 7)]" group-by="city"> <tr> <td>3-6</td> <td><xsl:value-of select="format-number(sum(current-group()/value),'$###,###')"/></td> </tr> </xsl:for-each-group> <xsl:for-each-group select="location[xs:integer(class) gt 6]" group-by="city"> <tr> <td>7-10</td> <td><xsl:value-of select="format-number(sum(current-group()/value),'$###,###')"/></td> </tr> </xsl:for-each-group> </xsl:variable> <xsl:perform-sort select="$rows"> <xsl:sort select="xs:decimal(replace(td[2], '[,$]', ''))" order="descending"/> </xsl:perform-sort> Having to do the replace after the formatting is probably not the right approach but you could in the first step only store the number values and in the second step sort and format if wanted.
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