I found the section on operations on times particularly challenging to
understand. I appreciate the precision of the definitions but the lack of
practical examples for some things makes it harder to translate into
practice.

Cheers,

E.
--
Eliot Kimber
http://contrext.com
 






On 10/6/16, 4:02 PM, "Michael Kay mike@xxxxxxxxxxxx"
<xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> wrote:

>A lot of people miss this one. By providing a convenient operator for
>this common operation, we ensured that people searching the function
>library wouldn't find it...
>
>Michael Kay
>Saxonica
>
>> On 6 Oct 2016, at 13:37, Eliot Kimber ekimber@xxxxxxxxxxxx
>><xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> wrote:
>> 
>> I think that's what I missed: I didn't realize you could do arithmetic
>> that directly.
>> 
>> I'll try it.
>> 
>> Cheers,
>> 
>> Eliot
>> --
>> Eliot Kimber
>> http://contrext.com
>> 
>> 
>> 
>> 
>> 
>> 
>> 
>> On 10/6/16, 12:24 PM, "Jirka Kosek jirka@xxxxxxxx"
>> <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> wrote:
>> 
>>> On Thu, Oct 6, 2016, at 11:40, Eliot Kimber ekimber@xxxxxxxxxxxx wrote:
>>>> I'm using XSLT to extract timing information from logs in order to
>>>> determine the duration of actions. Each log item has a time stamp in
>>>>the
>>>> usual format (2016-10-05T15:52:17.525:+0200).
>>> 
>>> And why are you simply not just subtracting two dateTimes, something
>>> like:
>>> 
>>> xs:dateTime("2015-01-01T12:00:00Z") -
>>> xs:dateTime("2014-07-10T12:00:00Z")
>>> 
>>> This will give you back duration. Or perhaps I have misunderstood...
>>> 
>>> Jirka
>>> 
>>> -- 
>>> ------------------------------------------------------------------
>>> Jirka Kosek      e-mail: jirka@xxxxxxxx      http://xmlguru.cz
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