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I am wondering how one would write the identity transformation template
<xsl:template match="@* | node()">
<xsl:copy>
<xsl:apply-templates select="@* | node()"/>
</xsl:copy>
</xsl:template>in an XSLT 3.0 stylesheet supposed to work with streaming. The section http://www.w3.org/TR/xslt-30/#built-in-templates-shallow-copy in the XSLT 3.0 specification has a template <xsl:template match="." mode="M">
<xsl:copy validation="preserve">
<xsl:apply-templates select="@*" mode="M"/>
<xsl:apply-templates select="node()" mode="M"/>
</xsl:copy>
</xsl:template>and explains "A further reason for choosing this form is for streamability: this formulation is guaranteed-streamable". However, when I try <xsl:stylesheet version="3.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xs="http://www.w3.org/2001/XMLSchema" exclude-result-prefixes="xs"> <xsl:mode streamable="yes"/> <xsl:template match=".">
<xsl:copy validation="preserve">
<xsl:apply-templates select="@*"/>
<xsl:apply-templates select="node()"/>
</xsl:copy>
</xsl:template></xsl:stylesheet> with Saxon 9.6 EE I get a compilation error saying: Error at xsl:template on line 8 column 25 of test2015012505.xsl: XTSE3430: Template rule is declared streamable but it does not satisfy the streamability rules. * In a streaming apply-templates instruction, the select expression cannot select ancestors or attributes (that is, it must not have climbing posture) So how would one write a template doing a shallow copy and then processing any attribute and child nodes in a streaming way?
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