Re: [xsl] Only child test

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Subject: Re: Only child test
From: "G. Ken Holman" <gkholman@xxxxxxxxxxxxxxxxxxxx>
Date: Thu, 10 Oct 2013 00:45:00 -0400

At 2013-10-09 21:38 -0700, you wrote:

Just curious how other's might approach a test to determine if the
current node is *not* an only child. This works fine but it feels a
little heavy to me.  Thoughts?

                <xsl:if test="(count(preceding-sibling::*) +
count(following-sibling::*)) &gt; 1">
                    <hr/>
                </xsl:if>

I think you need "... >0" in your test above to know that the current element has no siblings.

But if you know your current node is an element you could ask:

test="count(../*)!=1"

... which would return true if the current element is not an only child element.

I hope this helps.

. . . . . . Ken


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Current Thread
Only child test Karl Stubsjoen - 10 Oct 2013 04:39:12 -0000 Message not available G. Ken Holman - 10 Oct 2013 04:45:17 -0000 <= Michael Kay - 10 Oct 2013 06:34:00 -0000 Вячеслав Седов - 10 Oct 2013 08:42:12 -0000 David Carlisle - 10 Oct 2013 08:49:48 -0000 Michael Kay - 10 Oct 2013 09:02:24 -0000

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