If I have a template matching an attribute, and producing one in the output tree, like this:

  <xsl:template match="@style">
        <xsl:attribute name="style" select="."/>
  </xsl:template>

  <xsl:template match="@style">
     <xsl:copy-of select="."/>
  </xsl:template>

Is there any way to know the name of the element in the result tree which is the parent of the attribute being created?

Some context: I'm turning TEI @style attributes into HTML @style attributes in the output, and I'd like to handle situations in which this kind of input:

<hi rend="text-align: center;">Centred text</hi>

results in output that doesn't work:

<span style="text-align: center;">NOT centred because it's a span</span>

If I knew the output element was a <span> or element which is inline by default, I could add "display: block" automatically to any @style attribute that contains a block-level CSS property such as text-align. I don't want to add "display: block" in all cases, because e.g. a <div> element might already have a class which floats it.

  <xsl:template match="some-block-element">
    <div>
      <xsl:apply-templates>
        <xsl:with-param name="in-a-div" tunnel="yes" select="true()"/>
      </xsl:apply-templates>
    </div>
  </xsl:template>

  <xsl:template match="@style">
    <xsl:param name="in-a-div" tunnel="yes" select="false()"/>
    <xsl:attribute name="style"
      select="concat(.,if( $in-a-div ) then ';display:block' else'')"/>
    </xsl:attribute>
  </xsl:template>

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