Subject: Re: [XPath 3.0] How to do partial function application on the min() function?
From: Michael Kay <mike@xxxxxxxxxxxx>
Date: Mon, 29 Oct 2012 22:20:04 +0000
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The first argument of min is a sequence, and the second argument is a
collation. So you don't want to fix one argument, you want to fix part
of one argument.
Try
let $min2 := function($x) { min(($x, 2)) }
return $min2(3)
There is more than one way to skin a cat....
Michael Kay
Saxonica
On 29/10/2012 21:50, Costello, Roger L. wrote:
Hi Folks,
I would like to fix one argument of the min() function to 2 and leave the other argument undefined, thus producing a partially applied function. Then, I would like to give the partially applied function a value. Here's what I tried:
let $min2 := min((?,2))
return $min2(3)
I get this error: Unexpected token "?" in path expression
What's the correct way to accomplish this?
/Roger
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