For the ones interested ... I wrote an article explaining 2 approaches used to
solve the problem:

http://robbypelssers.blogspot.nl/2012/07/splitting-xml-content-into-multiple.
html

Thx for the help !!
Robby

-----Original Message-----
From: Robby Pelssers [mailto:Robby.Pelssers@xxxxxxx]
Sent: Monday, July 02, 2012 12:53 PM
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: RE:  copying namespaces question

It seems like great minds think alike !! ;-)

Thx a lot (again)... !!!!

Robby

-----Original Message-----
From: Andrew Welch [mailto:andrew.j.welch@xxxxxxxxx]
Sent: Monday, July 02, 2012 12:50 PM
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: Re:  copying namespaces question

On 2 July 2012 11:40, Michael Kay <mike@xxxxxxxxxxxx> wrote:
> I think I would do it like this:

bah, as I was typing it out....

<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
    version="2.0">

    <xsl:output indent="yes"/>

    <xsl:template match="@* | node()">
        <xsl:copy>
            <xsl:apply-templates select="@* ,node()"/>
        </xsl:copy>
    </xsl:template>

    <xsl:template match="/">
        <xsl:for-each select="//*:object">
            <xsl:result-document href="path/to/{*:name}.xml">
                <xsl:apply-templates select="root(.)/*">
                    <xsl:with-param name="current-object" select="."
tunnel="yes"/>
                </xsl:apply-templates>
            </xsl:result-document>
        </xsl:for-each>
    </xsl:template>

    <xsl:template match="*:object">
        <xsl:param name="current-object" tunnel="yes"/>
        <xsl:if test=". is $current-object">
            <xsl:copy>
                <xsl:apply-templates select="@*, node()"/>
            </xsl:copy>
        </xsl:if>
    </xsl:template>

</xsl:stylesheet>


--
Andrew Welch
http://andrewjwelch.com