Subject: Re: how to achieve this ?
From: Boudewijn Bosgoed <bbosgoed@xxxxxxx>
Date: Mon, 23 Jan 2012 08:35:36 +0100
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Op 23 jan 2012, om 08:26 heeft Roelof Wobben het volgende geschreven:
Not knowing how the input looks like, i would say that:
<ul class="menu" id={concat('menu', @value)}>
should do it for you, its a short notation for xsl:value-of select
> For a menu I have to take care that every <menu class> get a unique id.
>
> I thought this would work :
>
> <xsl:template match="year">
> <ul class="menu" id= "concat ('menu', @value)" >
> <li>
> <a href="#"> <xsl:value-of select="@value"/> </a>
> <ul class="acitem">
> <xsl:apply-templates select="month" />
> </ul>
> </li>
> </ul>
> </xsl:template>
>
> But it don't work.
>
> Do I have to use here <xsl:value-of> or is there a better way ?
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