hello,

I've tried this:

zxsl:value-of select="saxon:line-number(.)"/>
</xsl:template>

buy gives me the line of the input xml

I need to know the line number in the xslt itself

Many thanks

Bye

Il giorno ven, 02/12/2011 alle 13.01 +0000, Michael Kay ha scritto:
> You could implement the preprocessor easily enough if you are using 
> Saxon. For example if you use <?line?> then you can write the 
> preprocessor as
> 
> <xsl:template match="*">
>    .. identity template ..
> </xsl:template>
> 
> <xsl:template match="processing-instruction(line)">
> <xsl:value-of select="saxon:line-number(.)"/>
> </xsl:template>
> 
> Michael Kay
> Saxonica
> 
> On 02/12/2011 12:14, Bartolomeo Nicolotti wrote:
> > To whom it may concern,
> >
> > in C there's a pre-processor directive
> >
> > __LINE__
> >
> > that gives you the line of source where the directive is.
> >
> > Is there an equivalent in XSLT?
> >
> > Many thanks
> >
> > Best regards
> >
> > Bartolomeo