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Hi Ken,
I removed the [1] at the end to get all of the returns, and for the second example a '50' is returned, the @denomination[5] and the default [0]. It is clear that the @souvenir-sheet value is ignored in both cases. I am using XSLT 2, so it always collapses. Is there something incorrect with ../Location[name(@*)=name(current()/@*)] It seems correct to me. Mark -----Original Message----- From: Mark Sent: Sunday, October 23, 2011 5:39 PM To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Subject: Re: Can a single XPath statement duplicate the functionality of this verbose statement? Hi Ken, Yes, only one attribute to either element. You said:
xsl:copy-of select="( ../Location[name(@*)=name(current()/@*)] ,
../Location/@denomination ,
'0' )[1]"/>but I may have explained my needs incorrectly. Your statement works on the first example below [uses @denomination] but returns nothing for the second example; there it should return the value of the <Locations @souvenir-sheet>, i.e., '1'. Thanks, Mark <Stamp>
<Formats souvenir-sheet="2895"/>
<Location denomination="1"/>
</Stamp><Stamp>
<Formats souvenir-sheet="2896"/>
<Location denomination="5"/>
<Location souvenir-sheet="1"/>
</Stamp>
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