Subject: Re: HST's answers Re: Efficient way to check sequence membership -
From: Mukul Gandhi <gandhi.mukul@xxxxxxxxx>
Date: Thu, 3 Mar 2011 16:11:54 +0530
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On Thu, Mar 3, 2011 at 3:02 PM, Henry S. Thompson <ht@xxxxxxxxxxxx> wrote:
> As David Carlisle pointed out, '=' already supplies that
> functionality.
I think the XPath 2.0 operator '=' (one of the general comparison
operators) atomizes the operands so I think it won't check equality
based on node identity.
It seems the following expression can do checks based on node identity
(I inferred this meaning from Dave's requirement... the "member()"
function),
some $x in $seq satisfies ($x is $item)
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Regards,
Mukul Gandhi
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